You are given two 32-bit numbers, N and M, and two bit positions, i and j Write a method to set all bits between i and j in N equal to M (e g , M becomes a substring of N located at i and starting at j)

EXAMPLE:

Input: N = 10000000000, M = 10101, i = 2, j = 6 Output: N = 10001010100

第一个方法是我的思路 第二个是参考答案的思路实现的

#include 
    
     #include 
     
      using namespace std;typedef int Data;void setBits(bitset<32>* N, bitset<32>* M, int i, int j){    *N = *N^(*N<<(32-j+i-1)>>(32-j-1))^(*M<
      
       * N, bitset<32>* M, int i, int j){    bitset<32> t((~0<<(j+1)|((1<
       
         N((string)"10000000000");    bitset<32> M((string)"10101");    int i=2, j=6;    setBits2(&N, &M, i, j);    cout<
        
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